document.write( "Question 878772: Chris runs at 8 m/sec and Randy runs at a rate of 10 m/sec. If chis has a 10 second head start when will randy catch up to Chris (if ever)? Please help I've been struggling over this for hours I learned how to solve these types of problems months ago but I can't remember how to even set it up! \n" ); document.write( "
Algebra.Com's Answer #530263 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! R*T=D, rate unit is meters per second.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let t = time that Randy runs, which is 10 seconds less than the time Chris runs. Chris going slower, needs less time than than Randy.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "d is some unknown distance which Chris and Randy each run.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "________________speed_______time______distance \n" ); document.write( "Chris___________8___________t+10______8(t+10) \n" ); document.write( "Randy___________10___________t________10t\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Again, their distances are equal when Randy meets Chris. \n" ); document.write( " \n" ); document.write( "Solve for t, time in seconds. \n" ); document.write( " |