document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=878787>Question 878787</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to know how to do this problem:\r<BR>\n" );
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document.write( "e^(2x) + 2e^x - 48 = 0\r<BR>\n" );
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document.write( "Could someone show me the steps on how to complete this problem?\r<BR>\n" );
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document.write( "Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #530250 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=530250\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> e^(2x) + 2e^x - 48 = 0<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28e%5Ex+-+6%29%2A%28e%5Ex+%2B+8%29+=+0 ALIGN=MIDDLE  ALT=\"%28e%5Ex+-+6%29%2A%28e%5Ex+%2B+8%29+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=e%5Ex+=+-8 ALIGN=MIDDLE  ALT=\"e%5Ex+=+-8\"   DISABLED_style= \"max-width:90%; height:auto;\" > won't work.<BR>\n" );
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