document.write( "Question 74020This question is from textbook Intermediate Algebra
\n" ); document.write( ": Simplify using rules of exponents\r
\n" ); document.write( "\n" ); document.write( "#26.
\n" ); document.write( "(2x^-1y^2)^-3\r
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\n" ); document.write( "\n" ); document.write( "#38.
\n" ); document.write( "(-2y^2/x)^-3\r
\n" ); document.write( "\n" ); document.write( "Thank you. \n" ); document.write( "
Algebra.Com's Answer #53024 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Simplify using rules of exponents
\n" ); document.write( "#26.
\n" ); document.write( "(2x^-1y^2)^-3
\n" ); document.write( "= 2^-3 * x^3 *y^-6
\n" ); document.write( "=x^3/(8y^6)
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\n" ); document.write( "#38.
\n" ); document.write( "(-2y^2/x)^-3
\n" ); document.write( "The negative on the exponent means \"invert\"; the 3 means \"cube\"
\n" ); document.write( "You get:
\n" ); document.write( "Invert: [x/(-2y^2)]^3
\n" ); document.write( "Cube: x^3 / (-8y^6)
\n" ); document.write( "Rewrite as:\r
\n" ); document.write( "\n" ); document.write( "= -[x^3/8y^6]\r
\n" ); document.write( "\n" ); document.write( "-------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \r
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