document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=878732>Question 878732</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have the quadratic 6x(-2x + 4) = 0.  I get 2 solutions 0 or 2 but my vertex, b^2/2a = -24, this seems impossible.  What solution do you get? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #530234 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=530234\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I have the quadratic 6x(-2x + 4) = 0.  I get 2 solutions 0 or 2 but my vertex, b^2/2a = -24, this seems impossible.  What solution do you get?<BR>\n" );
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document.write( "x of the vertex is (0+2)/2 = 1<BR>\n" );
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document.write( "f(1) = 6*(-2 + 4) = 12<BR>\n" );
document.write( "Vertex at (1,12)<BR>\n" );
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