document.write( "Question 878319: Jim, ken, and max have a bag of miniature candy bars. Jim takes 1/4 of all the bars, and ken and len each take 1/3 of all the bars. Max gets the remaining 4 bars. How many bars were there in the bag originally? How many bars did jim, ken, and len each get? I tried adding 1/4, 1/3, 1/3, and 4 and I got 4 11/12, which doesn't seem right. \n" ); document.write( "
Algebra.Com's Answer #530201 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Jim takes 1/4 of all the bars, and ken and len each take 1/3 of all the bars. Max gets the remaining 4 bars. \n" ); document.write( " How many bars were there in the bag originally? \n" ); document.write( " How many bars did jim, ken, and len each get?: \n" ); document.write( "; \n" ); document.write( "Let x = total no. of bars \n" ); document.write( "x = \n" ); document.write( "multiply by 12, cancel the denominators \n" ); document.write( "12x = 3x + 8x + 12(4) \n" ); document.write( "12x = 11x + 48 \n" ); document.write( "12x - 11x = 48 \n" ); document.write( "12x - 9x = 8x \n" ); document.write( "x = 48 bars originally \n" ); document.write( "then \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check 12 + 16 + 16 + 4 = 48 \n" ); document.write( " |