document.write( "Question 878319: Jim, ken, and max have a bag of miniature candy bars. Jim takes 1/4 of all the bars, and ken and len each take 1/3 of all the bars. Max gets the remaining 4 bars. How many bars were there in the bag originally? How many bars did jim, ken, and len each get? I tried adding 1/4, 1/3, 1/3, and 4 and I got 4 11/12, which doesn't seem right. \n" ); document.write( "
Algebra.Com's Answer #530201 by ankor@dixie-net.com(22740)\"\" \"About 
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Jim takes 1/4 of all the bars, and ken and len each take 1/3 of all the bars. Max gets the remaining 4 bars.
\n" ); document.write( " How many bars were there in the bag originally?
\n" ); document.write( " How many bars did jim, ken, and len each get?:
\n" ); document.write( ";
\n" ); document.write( "Let x = total no. of bars
\n" ); document.write( "x = \"1%2F4\"x + \"2%2F3\"x + 4
\n" ); document.write( "multiply by 12, cancel the denominators
\n" ); document.write( "12x = 3x + 8x + 12(4)
\n" ); document.write( "12x = 11x + 48
\n" ); document.write( "12x - 11x = 48
\n" ); document.write( "12x - 9x = 8x
\n" ); document.write( "x = 48 bars originally
\n" ); document.write( "then
\n" ); document.write( "\"1%2F4\" * 48 = 12 for jim
\n" ); document.write( "\"1%2F3\" * 48 = 16 for len & ken
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check 12 + 16 + 16 + 4 = 48
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