document.write( "Question 878683: What quantity of a 80% acid solution must be mixed with a 40% solution to produce 600 mL of a 50% solution? \n" ); document.write( "

Algebra.Com's Answer #530194 by harpazo(655) $\"\"$ $\"About$

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\n" ); document.write( "Let x be what we are looking for.\r
\n" ); document.write( "\n" ); document.write( "0.80x + 0.40x = 0.50(600)\r
\n" ); document.write( "\n" ); document.write( "1.20x = 300\r
\n" ); document.write( "\n" ); document.write( "1.20x = 300\r
\n" ); document.write( "\n" ); document.write( "x = 250\r
\n" ); document.write( "\n" ); document.write( "Now that we know x, multiply 0.80 by 250 to find the quantity of an 80% acid solution.\r
\n" ); document.write( "\n" ); document.write( "So, 250 * 0.80 = 200\r
\n" ); document.write( "\n" ); document.write( "The answer is 200. \r
\n" ); document.write( "\n" ); document.write( "If we want to know the quantity for the 40% acid solution, multiply 250 by 0.40.\r
\n" ); document.write( "\n" ); document.write( "So, 250 * 0.40 = 100.\r
\n" ); document.write( "\n" ); document.write( "Here is the Prove\r
\n" ); document.write( "\n" ); document.write( "Let x = 250 in the equation above.\r
\n" ); document.write( "\n" ); document.write( "0.80(250) + 0.40(250) = 300\r
\n" ); document.write( "\n" ); document.write( "200 + 100 = 300\r
\n" ); document.write( "\n" ); document.write( "300 = 300\r
\n" ); document.write( "\n" ); document.write( "Did you follow? The most important thing to master when dealing with word problems is setting up the right equation leading to the answer. This comes with practice. \r
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