document.write( "Question 878676: Solve
\n" ); document.write( "a) logx + log(x-9) = 1\r
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Algebra.Com's Answer #530189 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"log%28%28x%29%29%2Blog%28%28x-9%29%29=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%28%28x%28x-9%29%29%29=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x-9%29=10%5E1\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x-9%29=10\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-9x=10\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-9x-10=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-10%29%28x%2B1%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x-10=0\" or \"x%2B1=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=10\" or \"x=-1\"\r
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\n" ); document.write( "\n" ); document.write( "The possible answers are \"x=10\" or \"x=-1\"; however, the domain of \"log%28%28x%29%29\" is \"x%3E0\". \r
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\n" ); document.write( "\n" ); document.write( "So that leaves out \"x=-1\" since it is NOT in the domain of \"log%28%28x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "The only solution is \"x=10\"
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