document.write( "Question 878660: how much money would have had to be invested to earn $436 simple interest at 1 percent for 2 years \n" ); document.write( "
Algebra.Com's Answer #530181 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! I = P*r*t\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "436 = P*0.01*2\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "436 = P*0.02\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "436/0.02 = P\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "21,800 = P\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P = 21,800\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You need to invest $21,800 \n" ); document.write( " |