document.write( "Question 878648: Solve
\n" ); document.write( "a) log(base 8)(x+1) - logx = 2\r
\n" ); document.write( "\n" ); document.write( "Can you please help me out? Thanks so much in advance:)
\n" ); document.write( "

Algebra.Com's Answer #530178 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming the problem is \"log%288%2C%28x%2B1%29%29-log%288%2C%28x%29%29=2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If so, then...\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"log%288%2C%28x%2B1%29%29-log%288%2C%28x%29%29=2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"log%288%2C%28%28x%2B1%29%2Fx%29%29=2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28x%2B1%29%2Fx=8%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28x%2B1%29%2Fx=64\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%2B1=64x\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"1=64x-x\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"1=63x\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"1%2F63=x\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=1%2F63\"
\n" ); document.write( "
\n" );