document.write( "Question 878563: A man has 30m of fencing. With it, he encloses 100m^2 of his garden, the boundary fence forming one side of the enclosure. What are the possible dimensions of the enclosure? \n" ); document.write( "
Algebra.Com's Answer #530143 by josgarithmetic(39623)\"\" \"About 
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The length of fencing is made into three sides. 30-2x and x are the dimensions of the garden. Letting x = one of the sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2830-2x%29=100\" gives the area equation of one dimension multiplied by the other dimension.\r
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\n" ); document.write( "\n" ); document.write( "\"-2x%5E2%2B30x=100\"
\n" ); document.write( "\"2x%5E2-30x=-50\"
\n" ); document.write( "\"x%5E2-15x%2B50=0\"
\n" ); document.write( "\"%28x-5%29%28x-10%29=0\"
\n" ); document.write( "\"x=5\" or \"x=10\"\r
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\n" ); document.write( "\n" ); document.write( "Other side is \"30-2%2A5=20\" or \"30-2%2A10=10\".\r
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\n" ); document.write( "\n" ); document.write( "Dimensions can be 5 by 20, or 10 by 10.
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