document.write( "Question 878462: Mike's Resume shop specializes in creating resumes for students. A recent survey of Mike's shop revealed that a spelling error was made on 10% of the resumes last year. Calculate the probabilities that a certain number of resumes have spelling errors assuming this rate continues into this year and they prepare 5370 resumes.
\n" ); document.write( "For full marks your answer should be accurate to at least four decimal places.\r
\n" ); document.write( "\n" ); document.write( "a) More than 530 resumes. \r
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\n" ); document.write( "\n" ); document.write( "b) At least 530 resumes. \r
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\n" ); document.write( "\n" ); document.write( "c) Exactly 530 resumes. \r
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Algebra.Com's Answer #530115 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi
\n" ); document.write( "I. recommend using a TI Calculator...
\n" ); document.write( "II. Must Learn when to recognize a Binomial Distribution, when You see one.
\n" ); document.write( "Most recognizable when You see a % of a certain event given. Generally when samples are very Large(>1000),
\n" ); document.write( "one uses a normal approximation to the binomial.
\n" ); document.write( "Trick is: When Using the normal approxiamation, one uses 'endpoints' (using .5)
\n" ); document.write( "a)p(error) = .10, n = 5370, mean = 537 and SD = sqrt(537*.90) = 21.98
\n" ); document.write( "P(x > 530) = 1 - P(z ≤ (\"++highlight_green%28530.5%29+\" - 537)/21.98 = 1- P(z ≤ -.2957) = 1 - .3837= .6163
\n" ); document.write( "b) P(x ≤ 530) = P(z ≤ -.2957) = .3837
\n" ); document.write( "c) P(x = 530) = P(z ≤ -.2957) - P(z ≤ (\"++highlight_green%28529.5%29+\" - 537)/21.98 =.3837 - .3665 = .0172
\n" ); document.write( "Again, while it is not to 4 decimal points.. one can verify this using stattrek.com (Binomial distributions)
\n" ); document.write( "If Using TI...Using syntax: normalcdf(smaller, larger, µ, σ).
\n" ); document.write( "normalcdf(-9999, 530.5, 537, 21.98) and normal(-9999,529.5,537, 21.98)
\n" ); document.write( "would have made short work of this
\n" ); document.write( "Note: The -9999 is used as the smaller value to be at least 5 standard deviations from the mean. \n" ); document.write( "
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