document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=878595>Question 878595</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Your friend is having a wedding party in her backyard and she is looking for an expert to set up a creative lighting plan for the event.Your task is to create LED lighting series circuit that will provide enough light so the party area is covered in lights.\r<BR>\n" );
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document.write( "The yard forms a rectangle and is 34yards wide by 48 yards long\r<BR>\n" );
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document.write( "At 6 feet high off the ground the light fixture covers an area 1.41 by 1.03 feet.for every additional foot the light is off the ground its coverage area increase by 10% the highest the lamp uses 7 volts and 18amps<BR>\n" );
document.write( "You will need to use batteries to power the fixture.a battery can produce 199volts of power\r<BR>\n" );
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document.write( "You need to make sure you do not exceed 20amp fuse in the circuit\r<BR>\n" );
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document.write( "1.what is the area of yards?<BR>\n" );
document.write( "2.the light fixture at six off the ground provides____sq.yards of coverage area<BR>\n" );
document.write( "3.At seven feet off the ground the light fixtures area of coverage is increased by__% and is now covering___sq.yards </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #530113 by </B><A HREF=/tutors/aboutme.mpl?userid=Jstrasner><B>Jstrasner(112)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Jstrasner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Jstrasner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=530113\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello,\r<BR>\n" );
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document.write( "So first we need to find the area of the yard which is simply length times width:\r<BR>\n" );
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document.write( "34 yards x 48 yards = 1632 square yards. Question 1.\r<BR>\n" );
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document.write( "Next,\r<BR>\n" );
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document.write( "we need to find the area of the coverage which is simply length times width:\r<BR>\n" );
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document.write( "1.41 feet x 1.03 feet = 1.4523 square feet. Question 2.\r<BR>\n" );
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document.write( "Lastly, \r<BR>\n" );
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document.write( "we need know that each additional foot increases the coverage by 10%, so 7 feet, which is only one additional foot, has 10% more coverage so that is the first part answer to question 3. \r<BR>\n" );
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document.write( "We take the coverage from 6 feet and multiply it by 10%:\r<BR>\n" );
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document.write( "1.4523 square feet x 10% = .14523 square feet. \r<BR>\n" );
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document.write( "So at 7 feet, the coverage is 1.4523 square feet + .14523 square feet = 1.59753 square feet of coverage.<BR>\n" );
document.write( "Question 3.\r<BR>\n" );
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document.write( "I hope this helps! </SPAN>\n" );
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