document.write( "Question 878428: Juan goes to work averaging 32 mph because traffic conditions. He return home at 38mph. His total time driving is 2.3 hrs. Find how long it took for him to get from work to home \n" ); document.write( "
Algebra.Com's Answer #530078 by ankor@dixie-net.com(22740)\"\" \"About 
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Juan goes to work averaging 32 mph because traffic conditions.
\n" ); document.write( " He return home at 38mph. His total time driving is 2.3 hrs.
\n" ); document.write( "Find how long it took for him to get from work to home
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\n" ); document.write( "Let t = his time from work to home
\n" ); document.write( "then
\n" ); document.write( "(2.3-t) = his time from home to work
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\n" ); document.write( "The dist there and back are the same.
\n" ); document.write( "Write a dist equation; dist = speed * time
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\n" ); document.write( "time back = time there
\n" ); document.write( "38t = 32(2.3-t)
\n" ); document.write( "38t = 73.6 - 32t
\n" ); document.write( "38t + 32t = 73.6
\n" ); document.write( "70t = 73.6
\n" ); document.write( "t = 73.6/70
\n" ); document.write( "t = 1.05 hr or 1 + .05(60) = 1 hr 3 min
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\n" ); document.write( "Check this; find the time there: 2.3 - 1.05 = 1.25 hrs
\n" ); document.write( "Find the dist each way, should be equal
\n" ); document.write( "1.25 * 32 = 40 mi
\n" ); document.write( "1.05 * 38 = 40 mi
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