document.write( "Question 73968: 1/(y-4)-2/(y-8)=-1/(y+6) \n" ); document.write( "
Algebra.Com's Answer #53007 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( ". \n" ); document.write( "Note that we can make everything have a common denominator. The common denominator is \n" ); document.write( "formed by multiplying together the denominators of all three fractions and is: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The first fraction on the left side already has \n" ); document.write( "we multiply the first fraction by \n" ); document.write( "multiplier has the same numerator as its denominator it is the same as multiplying by 1. \n" ); document.write( ". \n" ); document.write( "With this multiplication the first fraction becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Now let's work on the second fraction on the left side. \n" ); document.write( ". \n" ); document.write( "We do a similar process on the second fraction which is \n" ); document.write( "already has \n" ); document.write( " \n" ); document.write( "because this fraction contains the two factors that are missing for the common denominator. \n" ); document.write( "The result of this multiplication is: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Finally, let's work on the fraction on the right side of the equal sign. This fraction is: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and it is missing the two terms \n" ); document.write( "Therefore let's multiply this fraction by \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Now we can substitute all 3 of these converted fractions into the original problem to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Now we can multiply all terms on both sides by the common denominator and that will cancel \n" ); document.write( "out the common denominator from all terms just leaving us with the numerators as follows: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "On the right side drop the 1 and just keeping \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Next do all the multiplications. First, \n" ); document.write( "Next, \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Finally do the multiplication on the right side to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Put all these multiplications into the equation to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Combine the like terms on the left side. First you have \n" ); document.write( " \n" ); document.write( "on the left side the entire equation becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "This is further reduced by adding \n" ); document.write( "terms entirely. What is left is: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Subtract 12y from both sides to eliminate the 12y on the right side and the equation becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Get rid of the minus signs by multiplying both sides by -1 and you have: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and finally divide both sides by 18 to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "That's the answer. You can convert it to a proper fraction (1 and 7/9) or a decimal if you \n" ); document.write( "like. \n" ); document.write( ". \n" ); document.write( "It's been a long trip to get to the answer, but there is a lot of good practice involved in \n" ); document.write( "getting there. Hope this helps you to gain some insight into algebraic manipulations. \n" ); document.write( " |