document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=878559>Question 878559</A>: <I><SPAN STYLE=\"word-break: break-all;\"> describe the way that the surface Area of changes when each side is increase by %50. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #530061 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=530061\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Similar<BR>\n" );
document.write( "=-=-=-=-=-=-=-=-=-=-=-=-=-Surface area is a function of the square of the dimensions.<BR>\n" );
document.write( "SA = k*s^2<BR>\n" );
document.write( "SA*x = k*(0.9s)^2 = k*0.81s^2<BR>\n" );
document.write( "--> 19% decrease<BR>\n" );
document.write( " </SPAN>\n" );
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