document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=878366>Question 878366</A>: <I><SPAN STYLE=\"word-break: break-all;\"> From the top of a building, a rock is thrown straight up with an intial velocity of 32ft. per second. The equation s = -16t^2 + 32t + 48 gives is the height (s) of the rocks (t) seconds after its thrown. Find the maximum height reached by the rock. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #530038 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=530038\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From the top of a building, a rock is thrown straight up with an initial velocity of 32ft. per second. The equation s = -16t^2 + 32t + 48 gives is the height (s) of the rocks (t) seconds after its thrown. Find the maximum height reached by the rock.<BR>\n" );
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document.write( "s = -16t^2 + 32t + 48<BR>\n" );
document.write( "complete the square:<BR>\n" );
document.write( "s = -16(t^2-2t+1)+16 + 48<BR>\n" );
document.write( "s = -16(t-1)^2+64<BR>\n" );
document.write( "This is an equation of a parabola that opens downward with vertex at (1,80)<BR>\n" );
document.write( "maximum height reached by the rock=64 ft </SPAN>\n" );
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