document.write( "Question 73993: section 9.6 # 46\r
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\n" ); document.write( "\n" ); document.write( "Geometry. The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 5 cm, what are the dimensions (the length and width) of the rectangle?
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Algebra.Com's Answer #53001 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let L=length, w=width.
\n" ); document.write( "The length and width can be represented as
\n" ); document.write( "\"L=w%2B1\"
\n" ); document.write( "The diagonal of the rectangle is the hypotenuse of the triangle with legs of L and w. So the length and width can be found by Pythagoreans theorem.
\n" ); document.write( "\"%28L%29%5E2%2Bw%5E2=5%5E2\"Plug in w+1 into L
\n" ); document.write( "\"%28w%2B1%29%5E2%2Bw%5E2=25\"foil the (w+1)^2 term
\n" ); document.write( "\"w%5E2%2B2w%2B2%2Bw%5E2=25\"Combine like terms and get everything to one side
\n" ); document.write( "\"2w%5E2%2B2w-24=0\"
\n" ); document.write( "Plug this into the quadratic equation to solve for w
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"aw%5E2%2Bbw%2Bc=0\" (in our case \"2w%5E2%2B2w%2B-24+=+0\") has the following solutons:
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\n" ); document.write( " \"w%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%282%29%5E2-4%2A2%2A-24=196\".
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\n" ); document.write( " Discriminant d=196 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-2%2B-sqrt%28+196+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"w%5B1%5D+=+%28-%282%29%2Bsqrt%28+196+%29%29%2F2%5C2+=+3\"
\n" ); document.write( " \"w%5B2%5D+=+%28-%282%29-sqrt%28+196+%29%29%2F2%5C2+=+-4\"
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\n" ); document.write( " Quadratic expression \"2w%5E2%2B2w%2B-24\" can be factored:
\n" ); document.write( " \"2w%5E2%2B2w%2B-24+=+2%28w-3%29%2A%28w--4%29\"
\n" ); document.write( " Again, the answer is: 3, -4.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B2%2Ax%2B-24+%29\"

\n" ); document.write( "\n" ); document.write( "This means the width is 3 (the negative width is ignored since it's not practical). So the length is
\n" ); document.write( "\"L=w%2B1\"
\n" ); document.write( "\"L=3%2B1\"
\n" ); document.write( "\"L=4\"
\n" ); document.write( "So the dimensions are: Width=3,Length=4
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\n" ); document.write( "Check:
\n" ); document.write( "\"3%5E2%2B4%5E2=5%5E2\"
\n" ); document.write( "\"9%2B16=25\"
\n" ); document.write( "\"25=25\"Works \n" ); document.write( "

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