document.write( "Question 73993: section 9.6 # 46\r
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document.write( "Geometry. The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 5 cm, what are the dimensions (the length and width) of the rectangle? \n" );
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Algebra.Com's Answer #53001 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Let L=length, w=width. \n" ); document.write( "The length and width can be represented as \n" ); document.write( " \n" ); document.write( "The diagonal of the rectangle is the hypotenuse of the triangle with legs of L and w. So the length and width can be found by Pythagoreans theorem. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Plug this into the quadratic equation to solve for w \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "This means the width is 3 (the negative width is ignored since it's not practical). So the length is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So the dimensions are: Width=3,Length=4 \n" ); document.write( "
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