document.write( "Question 878505: The legth of a rectangle is 1 less the 3 times its width. The permeter is 30.\r
\n" ); document.write( "\n" ); document.write( "How do you findthe length?
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Algebra.Com's Answer #529995 by erica65404(394)\"\" \"About 
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The first step is to write equations for length and width.
\n" ); document.write( "Length is 1 less than 3 times width or length is 3 times width minus 1.\r
\n" ); document.write( "\n" ); document.write( "\"L=3W-1\"
\n" ); document.write( "\"L\" is length and \"W\" is width.
\n" ); document.write( "Width on the other hand is simply \"W=W\".\r
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\n" ); document.write( "\n" ); document.write( "Now the equation for the perimeter is \"P=2L+%2B+2W\" or \"P=+L%2BL%2BW%2BW\". The first option is simpler.\r
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\n" ); document.write( "\n" ); document.write( "Plug in \"3W-1\" for \"L\" then solve for \"W\".\r
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\n" ); document.write( "\n" ); document.write( "\"30=+2%283W-1%29%2B2W\"
\n" ); document.write( "\"30=6W-2%2B2W\"
\n" ); document.write( "\"32=8W\"
\n" ); document.write( "\"W=4\"\r
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\n" ); document.write( "\n" ); document.write( "We are looking for length so we plug 4 back into length's equation.
\n" ); document.write( "\"L=3W-1\"
\n" ); document.write( "\"L=3%284%29-1\"
\n" ); document.write( "\"L=11\"\r
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\n" ); document.write( "\n" ); document.write( "Check answer.
\n" ); document.write( "\"30=2%2811%29%2B2%284%29\"
\n" ); document.write( "\"30=30\"\r
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\n" ); document.write( "\n" ); document.write( "The length is 11.
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