document.write( "Question 878432: The width of a rectangle is 11 inches less than its LENGTH. The area is 6 square yards. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #529969 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
The \"6p\" was assumed to be a mistake, and that \"6\" was intended.\r
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\n" ); document.write( "\n" ); document.write( "Use the numbers as inches and then after solving, convert to the units you believe best.\r
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\n" ); document.write( "\n" ); document.write( "\"w=-11%2BL\" and \"wL=6%2A36%2A36\" keeping all units in inches or square inches.
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\n" ); document.write( "\"%28L-11%29L=6%5E5\"
\n" ); document.write( "\"L%5E2-11L-6%5E5=0\"
\n" ); document.write( "\"L%5E2-11L-7776=0\"
\n" ); document.write( "discrim, 121+4*7776=31225=25*1249
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\n" ); document.write( "\"L=%2811%2B-+sqrt%2825%2A1249%29%29%2F2\"
\n" ); document.write( "\"highlight%28L=%2811%2B5sqrt%281249%29%29%2F2%29\"----one of the dimension, inches.
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\n" ); document.write( "\"w=-11%2B%2811%2B5sqrt%281249%29%29%2F2\"
\n" ); document.write( "\"w=%28-22%2B11%2B5sqrt%281249%29%29%2F2\"
\n" ); document.write( "\"highlight%28w=%28-11%2B5sqrt%281249%29%29%2F2%29\"---other dimension, inches.
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