document.write( "Question 878486: Any and all help with this problem is GREATLY appreciated!! I think maybe the phase shift is left 3.14\r
\n" ); document.write( "\n" ); document.write( "What are the amplitude, period, phase shift, and midline of f(x) = 7 cos(2x + π) − 3?
\n" ); document.write( "amplitude = −3; period: π; phase shift: x = negative pi over 2; midline: y = 3\r
\n" ); document.write( "\n" ); document.write( " amplitude: 7; period: π; phase shift: x = negative pi over 2; midline: y = −3\r
\n" ); document.write( "\n" ); document.write( " amplitude: 7; period: 2π; phase shift: x = pi over 2; midline: y = 3\r
\n" ); document.write( "\n" ); document.write( " amplitude: −3; period: 2π; phase shift: x = pi over 2; midline: y = −3
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Algebra.Com's Answer #529968 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
f(x) = 7 cos(2x + π) − 3 is in the form f(x) = A*cos(Bx - C) + D\r
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\n" ); document.write( "\n" ); document.write( "where\r
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\n" ); document.write( "\n" ); document.write( "A = 7
\n" ); document.write( "B = 2
\n" ); document.write( "C = -pi
\n" ); document.write( "D = -3\r
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\n" ); document.write( "\n" ); document.write( "Amplitude: |A| = |7| = 7\r
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\n" ); document.write( "\n" ); document.write( "Period: T = 2pi/B = 2pi/2 = pi\r
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\n" ); document.write( "\n" ); document.write( "Phase Shift: C/B = -pi/2 (so we're shifting left pi/2 units)\r
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\n" ); document.write( "\n" ); document.write( "Midline: D = -3 ---> y = -3\r
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\n" ); document.write( "\n" ); document.write( "Put that all together and you get choice B as the final answer.
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