document.write( "Question 878394: I have the problem
\n" ); document.write( "a rectangular piece of paper is three times as long as it is wide. From each of its corners the square of 3 cm is cut out. The flaps at each corner are then turned up to form an open box. The volume of the box is 189 cm³. Find the original dimensions of the piece of the paper.
\n" ); document.write( "A) 2cm x 21 cm
\n" ); document.write( "B) 4.6 cm x 13.8 cm
\n" ); document.write( "C) 9 cm x 27 cm
\n" ); document.write( "D) 25.8 cm x 77.4 cm \r
\n" ); document.write( "\n" ); document.write( "I'm not sure I am correct so far but this is what u have done
\n" ); document.write( "L x w x h = V
\n" ); document.write( "(3x)(x)(3) =189 cm³
\n" ); document.write( "9x^2 = 89 cm³\r
\n" ); document.write( "\n" ); document.write( "I don't know what to do next or if that's right so far. Please help, thanks so much!
\n" ); document.write( "

Algebra.Com's Answer #529924 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
The sheet is x by 3x
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\n" ); document.write( "After it's cut, it's x-6 by 3x-6
\n" ); document.write( "---
\n" ); document.write( "Vol = 3*(x-6)*(3x-6) = 189
\n" ); document.write( "(x-6)*(x-2) = 21 (make it easier)
\n" ); document.write( "\"x%5E2+-+8x+%2B+12+=+21\"
\n" ); document.write( "\"x%5E2+-+8x+-+9+=+0\"
\n" ); document.write( "x = 9 (Ignore the -1 solution)
\n" ); document.write( "--> 9 by 27
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