document.write( "Question 878372: Name a point that Square Root (2) units away from (2,7). I don't know where to start. I would appreciate the help. Thank you! \n" ); document.write( "

Algebra.Com's Answer #529899 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
You can add or subtract $\"sqrt%282%29\"$ to the x value of $\"2\"$ while keeping the y value at $\"7\"$ .
\n" ); document.write( "You can add or subtract $\"sqrt%282%29\"$ to the y value of $\"7\"$ while keeping the $\"x\"$ value at $\"2\"$ .
\n" ); document.write( "( $\"2%2Bsqrt%282%29\"$ , $\"7\"$ )
\n" ); document.write( "( $\"2-sqrt%282%29\"$ , $\"7\"$ )
\n" ); document.write( "( $\"2\"$ , $\"7%2Bsqrt%282%29\"$ )
\n" ); document.write( "( $\"2\"$ , $\"7-sqrt%282%29\"$ )
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\n" ); document.write( "In general, any point on the circle centered at ( $\"2\"$ , $\"7\"$ ) with a radius of $\"sqrt%282%29\"$ will also satisfy the condition.
\n" ); document.write( " $\"%28x-2%29%5E2%2B%28y-7%29%5E2=2\"$
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