document.write( "Question 878279: Mr.Walker travels a miles in b hours, and then c miles in d hours. How many hours would it take to travel 1000 miles if he maintains this average rates?
\n" ); document.write( "A. 1000/(a+c)
\n" ); document.write( "B. 1000/(b+d)
\n" ); document.write( "C. 1000/(b+c+d)
\n" ); document.write( "D. 1000(b+d)/(a+c)
\n" ); document.write( "E. (a+c)/1000 (b+d)
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Algebra.Com's Answer #529861 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
avg rate = \"%28a%2Bc%29%2F%28b%2Bd%29\"
\n" ); document.write( "\"1000%2F%28%28a%2Bc%29%2F%28b%2Bd%29%29+=+1000%28b%2Bd%29%2F%28a%2Bc%29\"
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