document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=878020>Question 878020</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Five cards are dealt from a standard deck of 52 cards. What is the probability that three or four of the cards are aces? (Show your work, answer can be in fraction or decimal form rounded to ten thousandths)\r<BR>\n" );
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document.write( "I have found the probability for there being three aces (1/5525) and the probability for there being four aces (1/270725). I just don't know what to do to combine them to make it so that it is three OR four. Thank you for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #529823 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=529823\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Best to keep Your Denominator intack: 52C5 is 2598960<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+P%283+0r+4%29+=+%284C3%29%2848C2%29%2F2598960+%2B+%284C4%29%2848C1%29%2F2598960+=+%284%2A1128+%2B+48%29%2F+2598960 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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