document.write( "Question 878141: 5^(2x+1)=2^x \n" ); document.write( "
Algebra.Com's Answer #529798 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"5%5E%282x%2B1%29=2%5Ex\"
\n" ); document.write( "\"log%28%285%5E%282x%2B1%29%29%29=log%28%282%5Ex%29%29\"
\n" ); document.write( "\"%282x%2B1%29%2Alog%28%285%29%29=x%2Alog%28%282%29%29\"
\n" ); document.write( "Substitute to make it easier to read,
\n" ); document.write( "\"%282x%2B1%29a=bx\"
\n" ); document.write( "\"2ax%2Ba=bx\"
\n" ); document.write( "\"%282a-b%29x=-a\"
\n" ); document.write( "\"x=%28-a%29%2F%282a-b%29\"
\n" ); document.write( "\"x=a%2F%28b-2a%29\"
\n" ); document.write( "\"highlight%28x=log%28%285%29%29%2F%28log%28%282%29%29-2%2Alog%28%285%29%29%29%29\"
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