document.write( "Question 878247: please help me to solve this question as tomorrow is my exam in maths
\n" ); document.write( "'two years ago, bunty was three times as old as his son and two years hence, twice his age is equal to five times that of his son.find their present ages.
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Algebra.Com's Answer #529774 by josgarithmetic(39618)\"\" \"About 
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x and y, bunty and son.
\n" ); document.write( "\"x-2=3%2A%28y-2%29\", the first part.\r
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\n" ); document.write( "\n" ); document.write( "The \"two years hence\" part:
\n" ); document.write( "\"2%28x%2B2%29=5%2A%28y%2B2%29\", but this may be ambiguous in the wording.\r
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\n" ); document.write( "\n" ); document.write( "Those then are two equations in the two unknown variables. \r
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\n" ); document.write( "\n" ); document.write( "Simplifications will give:
\n" ); document.write( "\"x-2=3y-6\"
\n" ); document.write( "\"x-3y=-6%2B2\"
\n" ); document.write( "\"highlight%28x-3y=-4%29\"
\n" ); document.write( "and
\n" ); document.write( "\"2x%2B4=5y%2B10\"
\n" ); document.write( "\"2x-5y=10-4\"
\n" ); document.write( "\"highlight%282x-5y=6%29\"
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\n" ); document.write( "Solve the system of the two equations.
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