document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=878249>Question 878249</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I don't know how to set this problem up:  Two cyclists start at the same point and travel in opposite directions. One travels 3mph faster than the other. In 2 hours they are 402 miles apart. How fast is each traveling? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #529768 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=529768\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The total distance is 402 miles.<BR>\n" );
document.write( "Let the faster cyclist be A and the slower, B.<BR>\n" );
document.write( "How many miles traveled in one hour? 201<BR>\n" );
document.write( "A + B = 201<BR>\n" );
document.write( "A = B + 3<BR>\n" );
document.write( "Substitute the value of A from the second equation into the first.<BR>\n" );
document.write( "(B+3) + B = 201<BR>\n" );
document.write( "2B + 3 = 201<BR>\n" );
document.write( "Subtract 3 from each side<BR>\n" );
document.write( "2B = 198<BR>\n" );
document.write( "B = 99<BR>\n" );
document.write( "If B = 99 mph, then A = 102 mph<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Obviously impossible ;-), unless they are MOTORbikes (doubtful even then!) </SPAN>\n" );
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