document.write( "Question 878201: Can you please help me solve this equation using quadratic formula?
\n" ); document.write( "0.25x^2-0.25x-10.5=0
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Algebra.Com's Answer #529749 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
\"0.25x%5E2-0.25x-10.5=0\"
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\n" ); document.write( "The quadratic formula says that the solutions (if any) to an equation of the form
\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\" are given by
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "However, I see no need to make work harder.
\n" ); document.write( "The coefficients of \"0.25x%5E2-0.25x-10.5=0\"
\n" ); document.write( "are ugly decimals, and they will make calculations complicated.
\n" ); document.write( "A much better looking equivalent equation can be obtained by multiplying both sides of the equal sign times 4:
\n" ); document.write( "\"0.25x%5E2-0.25x-10.5=0\"<-->\"4%280.25x%5E2-0.25x-10.5%29=4%2A0\"}<-->\"4%2A0.25x%5E2-4%2A0.25x-4%2A10.5=0\"<-->\"1x%5E2-1x-42=0\"
\n" ); document.write( "\"1x%5E2-1x-42=0\" is easier to solve by applying the quadratic formula.
\n" ); document.write( "(It is also easier to solve by factoring, and by \"completing the square\").
\n" ); document.write( "The equation \"1x%5E2-1x-42=0\" (usually written as \"x%5E2-x-42=0\"
\n" ); document.write( "has \"a=1\" , \"b=-1\" , and \"c=-42\" .
\n" ); document.write( "Applying the quadratic formula we get
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\n" ); document.write( "That means the solutions are
\n" ); document.write( "\"system%28x=%281+%2B+13%29%2F2=14%2F2=7%2C%22and%22%2Cx=%281-13%29%2F2=-12%2F2=-6%29\"
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\n" ); document.write( "NOTE:
\n" ); document.write( "Of course, you can always apply the quadratic formula to the original equation.
\n" ); document.write( "That is easy enough if you have someone else (or something else) do the calculations for you
\n" ); document.write( "I that case, you would use \"a=0.25\", \"b=-0.25\" , and \"c=-10.5\"
\n" ); document.write( "Then invoking the program available here,
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"0.25x%5E2%2B-0.25x%2B-10.5+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-0.25%29%5E2-4%2A0.25%2A-10.5=10.5625\".
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\n" ); document.write( " Discriminant d=10.5625 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--0.25%2B-sqrt%28+10.5625+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-0.25%29%2Bsqrt%28+10.5625+%29%29%2F2%5C0.25+=+7\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-0.25%29-sqrt%28+10.5625+%29%29%2F2%5C0.25+=+-6\"
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\n" ); document.write( " Quadratic expression \"0.25x%5E2%2B-0.25x%2B-10.5\" can be factored:
\n" ); document.write( " \"0.25x%5E2%2B-0.25x%2B-10.5+=+0.25%28x-7%29%2A%28x--6%29\"
\n" ); document.write( " Again, the answer is: 7, -6.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+0.25%2Ax%5E2%2B-0.25%2Ax%2B-10.5+%29\"

\n" ); document.write( "\n" ); document.write( "The automatic solver does not spell it out, but
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\n" ); document.write( "and \"sqrt%2810.5625%29=3.25\" , so it calculates the answers as
\n" ); document.write( " and
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