document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=878202>Question 878202</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help.. I have to solve this equation using quadratic formula<BR>\n" );
document.write( "0.3y^2+0.15y-11.7=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #529736 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=529736\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Without trying to know, the left side might be factorable, but your task is to use general solution.  Just follow that formula, substitute the values from your equation.  The general solution is easy to look for so your initial substitutions will be this:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=%28-0.15%2B-+sqrt%280.15%5E2-4%280.3%29%28-11.7%29%29%29%2F%282%2A0.3%29 ALIGN=MIDDLE  ALT=\"y=%28-0.15%2B-+sqrt%280.15%5E2-4%280.3%29%28-11.7%29%29%29%2F%282%2A0.3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Simplify and compute. </SPAN>\n" );
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