document.write( "Question 878130: name direction vertex Axis of symmetry focus diectrix of the parabola\r
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document.write( "x-1=1/4(y-8)^2\r
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document.write( "please help \n" );
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Algebra.Com's Answer #529729 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! name direction vertex, Axis of symmetry, focus, directrix of the parabola \n" ); document.write( "x-1=1/4(y-8)^2 \n" ); document.write( "(y-8)^2=4(x-1) \n" ); document.write( "This is an equation of a parabola that opens rightward. \n" ); document.write( "Its basic form: (y-k)^2=4p(x-k), (h,k)=coordinates of the vertex \n" ); document.write( "For given parabola: \n" ); document.write( "vertex: (1,8) \n" ); document.write( "axis of symmetry: y=8 \n" ); document.write( "4p=4 \n" ); document.write( "p=1 \n" ); document.write( "focus(2,8) \n" ); document.write( "directrix: x=0, or y-axis \n" ); document.write( "see graph below: \n" ); document.write( "y=±(4x-4)^.5+8 \n" ); document.write( " |