document.write( "Question 877943: Analyze the Conic Section (center, vertices intercepts ...)\r
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document.write( "(4x^2)+(9y^2)-40x+64 = 0
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Algebra.Com's Answer #529636 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Analyze the Conic Section (center, vertices intercepts ...) \n" ); document.write( "(4x^2)+(9y^2)-40x+64 = 0 \n" ); document.write( "4x^2-40x+9y^2=-64 \n" ); document.write( "complete the square \n" ); document.write( "4(x^2-10x+25)+9y^2=-64+100 \n" ); document.write( "4(x-5)^2+9y^2=36 \n" ); document.write( " \n" ); document.write( "This is an equation of an ellipse with horizontal major axis \n" ); document.write( "Its standard form of equation: \n" ); document.write( "For given ellipse: \n" ); document.write( "center: (5,0) \n" ); document.write( "a^2=9 \n" ); document.write( "a=3 \n" ); document.write( "length of major axis=2a=6 \n" ); document.write( "vertices: (5±a,0)=(5±3,0)=(2,0) and(8,0) \n" ); document.write( "b^2=4 \n" ); document.write( "b=2 \n" ); document.write( "length of minor axis=2b=4 \n" ); document.write( "x-intercept: \n" ); document.write( "set y=0 \n" ); document.write( "(x-5)^2/9=1 \n" ); document.write( "(x-5)^2=9 \n" ); document.write( "x-5=±√9=±3 \n" ); document.write( "x=5±3 \n" ); document.write( "x-intercept=2, 8 \n" ); document.write( ".. \n" ); document.write( "y-intercept \n" ); document.write( "set x=0 \n" ); document.write( "(-5)^2/9+y^2/4=1 \n" ); document.write( "y^2/4=1-25/9=-16/9 \n" ); document.write( "y^2=-64/9 \n" ); document.write( "y-intercept: none\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |