document.write( "Question 877946: The width of a rectangle is 4 inches less than half of the length. If the area of the rectangle is 42 square inches, find the dimensions. \n" ); document.write( "

Algebra.Com's Answer #529621 by josgarithmetic(39617) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"w=-4%2B%281%2F2%29L\"$ and $\"wL=42\"$ .\r
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\n" ); document.write( "\n" ); document.write( "The first part can be stated, $\"w=L%2F2-4\"$ .\r
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\n" ); document.write( "\n" ); document.write( " $\"%28L%2F2-4%29L=42\"$
\n" ); document.write( " $\"L%5E2%2F2-4L=42\"$
\n" ); document.write( " $\"L%5E2-8L=84\"$
\n" ); document.write( " $\"L%5E2-8L-84=0\"$ , factorable?
\n" ); document.write( " $\"%28L%2B6%29%28L-14%29=0\"$
\n" ); document.write( "Choose $\"highlight%28L=14%29\"$ .
\n" ); document.write( " $\"w=14%2F2-4=7-4=highlight%283=w%29\"$ . \n" ); document.write( "

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