document.write( "Question 877869: please help me with this problem:
\n" ); document.write( "A 15-foot ladder is place against the wall of a house, just reaching the bottom of a window whose still is 10 feet from the ground. Suddenly the ladder slips 4 feet down the wall of the house. How far is the foot of the ladder from the base of the house?
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Algebra.Com's Answer #529608 by ankor@dixie-net.com(22740)\"\" \"About 
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A 15-foot ladder is place against the wall of a house, just reaching the bottom of a window whose still is 10 feet from the ground.
\n" ); document.write( " Suddenly the ladder slips 4 feet down the wall of the house.
\n" ); document.write( " How far is the foot of the ladder from the base of the house?
\n" ); document.write( ":
\n" ); document.write( "The ladder is 6' off the ground after the 4' slip
\n" ); document.write( "Using pythag, the ladder is the hypotenuse, one leg is 6'
\n" ); document.write( "the other leg (d) is the distance the foot of the ladder is from the house
\n" ); document.write( ":
\n" ); document.write( "d^2 + 6^2 = 15^2
\n" ); document.write( "d^2 + 36 = 225
\n" ); document.write( "d^2 = 225 - 36
\n" ); document.write( "d^2 = 189
\n" ); document.write( "d = \"sqrt%28189%29\"
\n" ); document.write( "d = 13.75' from the base of the house
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