document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=73955>Question 73955</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me round angle measures to the nearest degree and side measures to the nearest tenth for this problem: A triangular garden has dimensions 54 feet, 48 feet, and 62 feet. Find the angles at each corner of the garden. (Law of Cosines) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #52959 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=52959\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a^2 = b^2+c^2-2bc(CosA)<BR>\n" );
document.write( "So, Cos(A)=[b^2+c^2-a^2]/2bc\r<BR>\n" );
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document.write( "Please help me round angle measures to the nearest degree and side measures to the nearest tenth for this problem: A triangular garden has dimensions 54 feet, 48 feet, and 62 feet. Find the angles at each corner of the garden. (Law of Cosines<BR>\n" );
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document.write( "Let \"48 ft\" be the side opposite angle A; then<BR>\n" );
document.write( "CosA = [54^2 + 62^2 - 48^2]/(2*54*62) <BR>\n" );
document.write( "CosA = [0.6654719...<BR>\n" );
document.write( "Take the cos^-1(A) to get A=48.28 degrees<BR>\n" );
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document.write( "Let \"54\" be the side opposite angle B; then<BR>\n" );
document.write( "CosB = [48^2+62^2-54^2]/(2*48*54] = 0.54301075...<BR>\n" );
document.write( "Take the cos^-1(B) to get B=57.111 degrees<BR>\n" );
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document.write( "Then the 3 angle is 180-48.28-57.11=74.61 degrees<BR>\n" );
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document.write( "Cheers,\r<BR>\n" );
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document.write( "Stan H.\r<BR>\n" );
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