document.write( "Question 877862: I have one gallon of acid 30% solution . I need to reduce it to 5% acid. How much water should I add? \n" ); document.write( "
Algebra.Com's Answer #529570 by jim_thompson5910(35256)\"\" \"About 
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\"I have one gallon of acid 30% solution\"\r
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\n" ); document.write( "\n" ); document.write( "So you have 1*0.30 = 0.30 gallons of pure acid.\r
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\n" ); document.write( "\n" ); document.write( "This means\r
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\n" ); document.write( "\n" ); document.write( "(amount of pure acid)/(total amount of solution) = (0.30)/(1) = 0.30\r
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\n" ); document.write( "\n" ); document.write( "which points back to the 30% acid solution\r
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\n" ); document.write( "\n" ); document.write( "Let x = amount of water to add (amount in gallons)\r
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\n" ); document.write( "\n" ); document.write( "If you add x gallons of water to the solution, you get 1+x total gallons (acid + water)\r
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\n" ); document.write( "\n" ); document.write( "so we now have\r
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\n" ); document.write( "\n" ); document.write( "(amount of pure acid)/(total amount of solution) = (0.30)/(1+x)\r
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\n" ); document.write( "\n" ); document.write( "You then take (0.30)/(1+x) and set that equal to 0.05 because you want to force the final solution to be 5% acid.\r
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\n" ); document.write( "\n" ); document.write( "So,\r
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\n" ); document.write( "\n" ); document.write( "(0.30)/(1+x) = 0.05\r
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\n" ); document.write( "\n" ); document.write( "Now solve for x\r
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\n" ); document.write( "\n" ); document.write( "(0.30)/(1+x) = 0.05
\n" ); document.write( "0.30 = 0.05(1+x)
\n" ); document.write( "0.30 = 0.05+0.05x
\n" ); document.write( "0.30-0.05 = 0.05x
\n" ); document.write( "0.25 = 0.05x
\n" ); document.write( "0.25/0.05 = x
\n" ); document.write( "5 = x
\n" ); document.write( "x = 5\r
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\n" ); document.write( "\n" ); document.write( "You need to add 5 gallons of pure water to dilute the 30% acid solution to a 5% acid solution.
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