document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=877777>Question 877777</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hypotenuse of a right triangle is 8 other two sides are unknown. Perimeter is 18, find the other legs. Round answers to three significant figures. I got 7.645 and 2.355. would be awesome if you could show me how to solve it mathematically, as i forgot what i did. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #529543 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39838)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=529543\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The legs are x and y.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2By%5E2=8%5E2 ALIGN=MIDDLE  ALT=\"x%5E2%2By%5E2=8%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > for the Pythagorean Theorem sides relationship, and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2By%2B8=18 ALIGN=MIDDLE  ALT=\"x%2By%2B8=18\"   DISABLED_style= \"max-width:90%; height:auto;\" > for the perimeter.\r<BR>\n" );
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document.write( "Perimeter equation goes through<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=10-x ALIGN=MIDDLE  ALT=\"y=10-x\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Substituting into right triangle pythagorean thm. equation,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B%2810-x%29%5E2=64 ALIGN=MIDDLE  ALT=\"x%5E2%2B%2810-x%29%5E2=64\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B100-20x%2Bx%5E2=64 ALIGN=MIDDLE  ALT=\"x%5E2%2B100-20x%2Bx%5E2=64\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-20x=64-100 ALIGN=MIDDLE  ALT=\"-20x=64-100\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=20x=36 ALIGN=MIDDLE  ALT=\"20x=36\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=36%2F20=18%2F10=9%2F5 ALIGN=MIDDLE  ALT=\"x=36%2F20=18%2F10=9%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Again using just the simplified relationship from perimeter equation,<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=50%2F5-9%2F5 ALIGN=MIDDLE  ALT=\"y=50%2F5-9%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28y=41%2F5%29 ALIGN=MIDDLE  ALT=\"highlight%28y=41%2F5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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