document.write( "Question 877742: center: (2,15)
\n" ); document.write( "point on circle: (5,15)
\n" ); document.write( "write the equation of each circle with the given information. then write the equation of the line tangent to the circle at the given point. (Hint: You will need both length and slope of the radius.)
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Algebra.Com's Answer #529531 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Find the radius by using the distance between the center and the point.
\n" ); document.write( "\"R%5E2=%282-5%29%5E2%2B%2815-15%29%5E2\"
\n" ); document.write( "\"R%5E2=%28-3%29%5E2\"
\n" ); document.write( "\"R=3\"
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\n" ); document.write( "\"%28x-2%29%5E2%2B%28y-15%29%5E2=9\"
\n" ); document.write( "Take the derivative to find the slope of the tangent line at any point,
\n" ); document.write( "\"2%28x-2%29%2B2%28y-15%29=0\"
\n" ); document.write( "\"%282x-4%29dx%2B%282y-30%29dy=0\"
\n" ); document.write( "\"%282y-30%29dy=%284-2x%29dx\"
\n" ); document.write( "\"dy%2Fdx=%284-2x%29%2F%282y-30%29\"
\n" ); document.write( "\"m=dy%2Fdx=%282-x%29%2F%28y-15%29\"
\n" ); document.write( "At \"x=5\",
\n" ); document.write( "\"m=%282-5%29%2F%2815-15%29\"
\n" ); document.write( "The slope is infinite at that point.
\n" ); document.write( "\"x=5\" is the tangent.
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