document.write( "Question 877646: A dishonest milk vendor purchased pure milk at Rs.10 per liter and sold diluted milk at Rs.10 per liter and gains a profit of 60%. What quantity of pure milk did he use in every liter? \n" ); document.write( "
Algebra.Com's Answer #529468 by ghostrecog(4)\"\" \"About 
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Let the vendor purchased a 10 liters of milk at Rs.10 per liter.
\n" ); document.write( "Then the total amount of purchase is 100.
\n" ); document.write( "he gained 60% profit after diluting.
\n" ); document.write( "Let x be rate of milk per liter.
\n" ); document.write( "and y be the total amount of liters\r
\n" ); document.write( "\n" ); document.write( "and w be the water added in order to dilute.\r
\n" ); document.write( "\n" ); document.write( "%gain = (new amount-old amount)/old amount
\n" ); document.write( "0.6= (x(y+w)-xy)/xy
\n" ); document.write( "w/y=0.6
\n" ); document.write( "w/y=6/10=3/5
\n" ); document.write( "This is clearly states that out of 8 liters, 3 liters of water is added with 5 liters of milk.
\n" ); document.write( "As per above statement total diluted milk =16 liters.
\n" ); document.write( "So there is 10 liters of pure milk in 16 liters of diluted milk.
\n" ); document.write( "Therefore each liter has a pure milk of =10/16 liters
\n" ); document.write( " =0.625 liters
\n" ); document.write( " =625 ml
\n" ); document.write( " \n" ); document.write( "
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