document.write( "Question 877648: a certain journey took 40 min to complete. if half of the distance was travelled at an average speed of 100 km/h and the other half at an average speed of 60 km/h, what was the length of the journey? i tried 180 km/h divided by 2 and then i got lost \n" ); document.write( "
Algebra.Com's Answer #529463 by josgarithmetic(39617)\"\" \"About 
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RT=D rate, time, distance.\r
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\n" ); document.write( "\n" ); document.write( "Distance is unknown.
\n" ); document.write( "Let d = journey distance.
\n" ); document.write( "\"40%2Ax=d%2F2\" and \"100%2Ay=d%2F2\" using x and y as the times for first half and second half of the journey distance. ALSO, \"x%2By=40%2F60\", since we could or should keep in units of time as hours.\r
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\n" ); document.write( "\n" ); document.write( "\"40x=100y\"
\n" ); document.write( "\"4x=10y\"
\n" ); document.write( "\"2x=5y\", from the R, T, D reationships.
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\n" ); document.write( "\"x%2By=2%2F3\", simplified form of the given time sum.
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\n" ); document.write( "Solve the system for x and y:
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\n" ); document.write( "\"highlight_green%282x=5y%29\" AND \"highlight_green%28x%2By=2%2F3%29\"
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\n" ); document.write( "\n" ); document.write( "When you know x and y, which are in HOURS, you can then find the journey's distance.
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