document.write( "Question 877639: Solve each equation \r
\n" ); document.write( "\n" ); document.write( "1. log7^4x = log7(3x+7)
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Algebra.Com's Answer #529456 by jim_thompson5910(35256)\"\" \"About 
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\"log%287%2C%284x%29%29=log%287%2C%283x%2B7%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"4x=3x%2B7\" Since the logs have the same base, and are equal to one another, this means the arguments (the stuff inside) must be equal\r
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\n" ); document.write( "\n" ); document.write( "\"4x-3x=7\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=7\"
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