document.write( "Question 877637: Find the solution of the exponential equation
\n" ); document.write( "100 (1.02)^(2t) = 50,000
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Algebra.Com's Answer #529452 by josgarithmetic(39808)\"\" \"About 
You can put this solution on YOUR website!
What you should already know:\r
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\n" ); document.write( "\n" ); document.write( "\"100%281.02%29%5E%282t%29=50000\"\r
\n" ); document.write( "\n" ); document.write( "\"%28100%2F100%291.02%5E%282t%29=50000%2F100\"\r
\n" ); document.write( "\n" ); document.write( "\"1.02%5E%282t%29=500\"\r
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\n" ); document.write( "\n" ); document.write( "What you are studying how to do now:\r
\n" ); document.write( "\n" ); document.write( "\"log%28%281.02%5E%282t%29%29%29=log%28%28500%29%29\"
\n" ); document.write( "\"2t%2Alog%28%281.02%29%29=log%28%285%2A10%5E2%29%29\"
\n" ); document.write( "\"2t%2Alog%28%281.02%29%29=2%2Alog%28%285%2A10%29%29\"
\n" ); document.write( "\"t%2Alog%28%281.02%29%29=log%28%285%2A10%29%29\"
\n" ); document.write( "\"t=log%28%285%2A10%29%29%2Flog%28%281.02%29%29\"\r
\n" ); document.write( "\n" ); document.write( "How to continue this depends on what base you want. Base ten might be most convenient.\r
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\n" ); document.write( "\n" ); document.write( "\"t=%28log%2810%2C5%2A10%29%29%2F%28log%2810%2C1.02%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"t=%28log%2810%2C5%29%2Blog%2810%2C10%29%29%2F%28log%2810%2C1.02%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28t=%28%28log%2810%2C5%29%29%2B1%29%2Flog%2810%2C1.02%29%29\"
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