document.write( "Question 73520: I solved this, but am not sure if I'm correct (the zero is making me think there's a trick):\r
\n" ); document.write( "\n" ); document.write( "1/6-1/3t>0\r
\n" ); document.write( "\n" ); document.write( "Here's what I came up with:
\n" ); document.write( "0/6-1/6+2/6 making t=1/6 which would be greater than 0. The interval notation would be: (0,1/6) and so on the graph, I would have two parentheses (one at zero, one at approximately 1/6). Did I do this correctly? Thank you for your assistance.
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Algebra.Com's Answer #52943 by tazoftroy(22)\"\" \"About 
You can put this solution on YOUR website!
Actually, t would be greater than 0, but not limited to 1/6.
\n" ); document.write( "You can rewrite the equation to be:
\n" ); document.write( "\"1%2A%283t%2F5%29%3E0\"
\n" ); document.write( "Then, multiplying by the reciprocal of 3/5 would just give \"t%3E0\"
\n" ); document.write( "So, the interval notation would be (0,+infinity)
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