document.write( "Question 877598: How many quarts of pure antifreeze must be added to 4 quarts of a 40% antifreeze solution to obtain a 60% antifreeze solution? \n" ); document.write( "
Algebra.Com's Answer #529426 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \"4 quarts of a 40% antifreeze solution\" ---> 4*0.40 = 1.6 quarts of pure antifreeze.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Adding some unknown amount, call it x, of pure antifreeze gives you 1.6+x quarts of pure antifreeze.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You have 4 quarts of a mixed solution and you're adding x quarts of pure antifreeze to the mix. \n" ); document.write( "So you end up with a total of 4+x quarts of mixed solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(amount of pure antifreeze)/(amount of solution) = percent of antifreeze\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(1.6 + x)/(4 + x) = 0.60\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1.6 + x = 0.60(4 + x)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1.6 + x = 0.60(4) + 0.60(x)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1.6 + x = 2.4 + 0.60x\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1.6 + x - 0.60x = 2.4\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x - 0.60x = 2.4 - 1.6\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0.40x = 0.8\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 0.8/0.40\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 2\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You need to add 2 quarts of pure antifreeze. \n" ); document.write( " |