document.write( "Question 877594: solve for z: e^2z-1 = 3
\n" ); document.write( "sorry i dont really know what topic this is. im just trying to answer my math module :(
\n" ); document.write( "

Algebra.Com's Answer #529419 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming the equation is \"e%5E%282z-1%29+=+3\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Use natural logs to isolate the exponent and then solve for z\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"e%5E%282z-1%29+=+3\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"ln%28e%5E%282z-1%29%29+=+ln%283%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%282z-1%29ln%28e%29+=+ln%283%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%282z-1%29%2A1+=+ln%283%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2z-1+=+ln%283%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2z+=+ln%283%29%2B1\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"z+=+%28ln%283%29%2B1%29%2F2\" <--- Exact Answer\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"z+=+1.04930614433406\" <--- Approximate Answer (use a calculator to evaluate, be sure to round appropriately if needed)
\n" ); document.write( "
\n" );