document.write( "Question 877210: The width of a rectangle is 7cm less than its length. Its area is 260cm squared. find the dimensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #529415 by ben720(159)\"\" \"About 
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\n" ); document.write( "Let Width = w
\n" ); document.write( "Let Length = w+7\r
\n" ); document.write( "\n" ); document.write( "\"w%2A%28w%2B7%29=260\" Because l*w = A
\n" ); document.write( "\"w%5E2%2B7w-260=0\"
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "\"x+=+%28-7+%2B-+sqrt%28+7%5E2-4%2A1%2A-260+%29%29%2F%282%2A1%29+\"
\n" ); document.write( "\"x=%28-7%2B-sqrt%2849%2B1040%29%29%2F2\"
\n" ); document.write( "\"x=%28-7%2B-sqrt%281089%29%29%2F2\"
\n" ); document.write( "The square root of 1089 is 33. Because both dimensions must be positive,
\n" ); document.write( "\"x=%28-7%2B33%29%2F2\"
\n" ); document.write( "\"x=26%2F2\"
\n" ); document.write( "x=13
\n" ); document.write( "The width is 13cm and the length is 20cm.
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