document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=877532>Question 877532</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is three more than twice the width. if the perimeter of a rectangle is 15,what is the length of the rectangle?\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #529396 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=529396\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=2w+3 and 2w+2L=15.<BR>\n" );
document.write( "Solve for w and L.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Notice that 15 is odd, so you might choose to not simplify the initial perimeter equation, although you could if you want.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Simple substitution:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2w%2B2%282w%2B3%29=15 ALIGN=MIDDLE  ALT=\"2w%2B2%282w%2B3%29=15\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and keep going... </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );