document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=877472>Question 877472</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the tenth term of the sequence that has a common ratio of 1/3 and 36 as it's fifth term? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #529356 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=529356\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a(n)=a(x)r^(x-5) where x is the number of the known term, in this case 5th (5), and n is the number of the term to be found, in this case 10th (10), and r is the common ratio.<P><BR>\n" );
document.write( "a(10)=36*(1/3)^(10-5) = 36*(1/3)^5 = .148148... </SPAN>\n" );
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