document.write( "Question 877458: Is it possible to have the following multiplication table? Give reasons\r
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Algebra.Com's Answer #529350 by Edwin McCravy(20055)\"\" \"About 
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document.write( "A A X B B = C C C\r\n" );
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document.write( "(10A+A)(10B+B) = 100C+10C+C\r\n" );
document.write( "    (11A)(11B) = 111C\r\n" );
document.write( "         121AB = 111C\r\n" );
document.write( "           \"AB%2FC\" = \"111%2F121\" \r\n" );
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document.write( "121 and 111 have no common factors other than 1. So\r\n" );
document.write( "For this to be an equality, the least AB and C could be is \r\n" );
document.write( "AB=111 and C=121. No digit C can be 121, since a digit \r\n" );
document.write( "is no larger than 9.  So it's not possible\r\n" );
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document.write( "Edwin

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