document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=877365>Question 877365</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters of a 6% solution of salt should be added to a 20% solution in order to obtain 630 liters of a 12% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #529304 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=529304\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Is the percent as mass per volume?  Simpler calculation if so.\r<BR>\n" );
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document.write( "x for the 6%<BR>\n" );
document.write( "y for the 20%\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%286x%2B20y%29%2F630=12 ALIGN=MIDDLE  ALT=\"%286x%2B20y%29%2F630=12\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2By=630 ALIGN=MIDDLE  ALT=\"x%2By=630\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
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