document.write( "Question 877290: sandra is 36 years old. her son is 1 years old. how many years ago was sandra 3 times older than her son? \n" ); document.write( "
Algebra.Com's Answer #529268 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
sandra is 36 years old. her son is 1 years old. how many years ago was sandra 3 times older than her son?
\n" ); document.write( "------------
\n" ); document.write( "The difference is 35 years.
\n" ); document.write( "3 times older = 4 times as old
\n" ); document.write( "-------
\n" ); document.write( "m = mother's age
\n" ); document.write( "s = son's age
\n" ); document.write( "---
\n" ); document.write( "m = s+35
\n" ); document.write( "m = 4s
\n" ); document.write( "---
\n" ); document.write( "4s = s+35
\n" ); document.write( "s = 35/3 years
\n" ); document.write( "m = 140/3 years
\n" ); document.write( "------
\n" ); document.write( "Years ago = 36 - 140/3 = negative age
\n" ); document.write( "No solution.
\n" ); document.write( "
\n" ); document.write( "
\n" );